Distance from Seminole to Jefferson City
Distance from Seminole to Jefferson City is 1,476 kilometers. This air travel distance is equal to 917 miles.
The air travel (bird fly) shortest distance between Seminole and Jefferson City is 1,476 km= 917 miles.
If you travel with an airplane (which has average speed of 560 miles) from Seminole to Jefferson City, It takes 1.64 hours to arrive.
Seminole
Seminole is located in United States.
| GPS Coordinates (DMS) | 27° 50´ 23.1000'' N 82° 47´ 28.3560'' W |
|---|---|
| Latitude | 27.83975 |
| Longitude | -82.79121 |
| Altitude | 16 m |
| Country | United States |
Seminole Distances to Cities
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |