Distance from Seminole to Albany
Distance from Seminole to Albany is 1,835 kilometers. This air travel distance is equal to 1,140 miles.
The air travel (bird fly) shortest distance between Seminole and Albany is 1,835 km or 1,140 miles.
If you travel with an airplane (which has average speed of 560 miles) from Seminole to Albany, It takes 2.04 hours to arrive.
Seminole
Seminole is located in United States.
| GPS Coordinates (DMS) | 27° 50´ 23.1000'' N 82° 47´ 28.3560'' W |
|---|---|
| Latitude | 27.83975 |
| Longitude | -82.79121 |
| Altitude | 16 m |
| Country | United States |
Seminole Distances to Cities
Albany
Albany is located in United States.
| GPS Coordinates | 42° 39´ 9.2880'' N 73° 45´ 22.4280'' W |
|---|---|
| Latitude | 42.65258 |
| Longitude | -73.75623 |
| Altitude | 50 m |
| Country | United States |
Albany Distances to Cities
| Albany | Distance |
|---|---|
| Distance from Albany Ny to Las Vegas | 3,598 km |
| Distance from Albany Ny to Kingston | 83 km |
| Distance from Albany Ny to Sacramento | 4,011 km |
| Distance from Albany Ny to San Francisco | 4,120 km |
| Distance from Albany Ny to Los Angeles | 3,956 km |