Distance from Searcy to Jefferson City
Distance from Searcy to Jefferson City is 371 kilometers. This air travel distance is equal to 231 miles.
The air travel (bird fly) shortest distance between Searcy and Jefferson City is 371 km or 231 miles.
If you travel with an airplane (which has average speed of 560 miles) from Searcy to Jefferson City, It takes 0.41 hours to arrive.
Searcy
Searcy is located in United States.
| GPS Coordinates (DMS) | 35° 15´ 2.3040'' N 91° 44´ 10.5000'' W |
|---|---|
| Latitude | 35.25064 |
| Longitude | -91.73625 |
| Altitude | 82 m |
| Country | United States |
Searcy Distances to Cities
| Searcy | Distance |
|---|---|
| Distance from Searcy to Tulsa | 398 km |
| Distance from Searcy to Starkville | 334 km |
| Distance from Searcy to Farmers Branch | 541 km |
| Distance from Searcy to Dallas | 542 km |
| Distance from Searcy to Oklahoma City | 526 km |
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |