Distance from Sayreville Junction to Trenton
Distance from Sayreville Junction to Trenton is 45 kilometers. This air travel distance is equal to 28 miles.
The air travel (bird fly) shortest distance between Sayreville Junction and Trenton is 45 km= 28 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sayreville Junction to Trenton, It takes 0.05 hours to arrive.
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates (DMS) | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |
Sayreville Junction Distances to Cities
Trenton
Trenton is located in United States.
| GPS Coordinates | 40° 13´ 1.3800'' N 74° 44´ 34.5840'' W |
|---|---|
| Latitude | 40.21705 |
| Longitude | -74.74294 |
| Altitude | 23 m |
| Country | United States |