Distance from Sao Goncalo do Sapucai to Aracaju
Distance from São Gonçalo do Sapucaí to Aracaju is 1,517 kilometers. This air travel distance is equal to 943 miles.
The air travel (bird fly) shortest distance between São Gonçalo do Sapucaí and Aracaju is 1,517 km= 943 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sao Goncalo do Sapucai to Aracaju, It takes 1.68 hours to arrive.
Sao Goncalo do Sapucai
Sao Goncalo do Sapucai is located in Brazil.
| GPS Coordinates (DMS) | 21° 53´ 31.9920'' S 45° 35´ 43.0080'' W |
|---|---|
| Latitude | -21.89222 |
| Longitude | -45.59528 |
| Altitude | 866 m |
| Country | Brazil |
São Gonçalo do Sapucaí Distances to Cities
Aracaju
Aracaju is located in Brazil.
| GPS Coordinates | 10° 54´ 39.9960'' S 37° 4´ 18.0120'' W |
|---|---|
| Latitude | -10.91111 |
| Longitude | -37.07167 |
| Altitude | 11 m |
| Country | Brazil |
Aracaju Distances to Cities
| Aracaju | Distance |
|---|---|
| Distance from Aracaju to Adamantina | 1,911 km |
| Distance from Aracaju to Alagoinhas | 200 km |
| Distance from Aracaju to Porto Velho | 2,952 km |
| Distance from Aracaju to Tefe | 3,163 km |
| Distance from Aracaju to Manaus | 2,677 km |