Distance from Sandy Springs to Jefferson City
Distance from Sandy Springs to Jefferson City is 870 kilometers. This air travel distance is equal to 541 miles.
The air travel (bird fly) shortest distance between Sandy Springs and Jefferson City is 870 km or 541 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sandy Springs to Jefferson City, It takes 0.97 hours to arrive.
Sandy Springs
Sandy Springs is located in United States.
| GPS Coordinates (DMS) | 33° 55´ 27.3720'' N 84° 22´ 42.7440'' W |
|---|---|
| Latitude | 33.92427 |
| Longitude | -84.37854 |
| Altitude | 333 m |
| Country | United States |
Sandy Springs Distances to Cities
| Sandy Springs | Distance |
|---|---|
| Distance from Sandy Springs to Tucker | 17 km |
| Distance from Sandy Springs to Glendale Az | 2,569 km |
| Distance from Sandy Springs to North Augusta | 229 km |
| Distance from Sandy Springs to Savannah | 368 km |
| Distance from Sandy Springs to Nashville | 332 km |
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |