Distance from San Fernando del Valle de Catamarca to Junin
Distance from San Fernando del Valle de Catamarca to Junín is 819 kilometers. This air travel distance is equal to 509 miles.
The air travel (bird fly) shortest distance between San Fernando del Valle de Catamarca and Junín is 819 km or 509 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Fernando del Valle de Catamarca to Junin, It takes 0.91 hours to arrive.
San Fernando del Valle de Catamarca
San Fernando del Valle de Catamarca is located in Argentina.
GPS Coordinates (DMS) | 28° 28´ 10.4520'' S 65° 47´ 6.8640'' W |
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Latitude | -28.46957 |
Longitude | -65.78524 |
Altitude | 545 m |
Country | Argentina |
San Fernando del Valle de Catamarca Distances to Cities
San Fernando del Valle de Catamarca | Distance |
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Distance from San Fernando Del Valle De Catamarca to Parana | 623 km |
Distance from San Fernando Del Valle De Catamarca to Rosario | 699 km |
Distance from San Fernando Del Valle De Catamarca to Rio Gallegos | 2,587 km |
Distance from San Fernando Del Valle De Catamarca to Rawson | 1,647 km |
Distance from San Fernando Del Valle De Catamarca to Machagai | 591 km |
Junin
Junin is located in Argentina.
GPS Coordinates | 34° 35´ 1.7520'' S 60° 56´ 35.9520'' W |
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Latitude | -34.58382 |
Longitude | -60.94332 |
Altitude | 83 m |
Country | Argentina |
Junín Distances to Cities
Junín | Distance |
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Distance from Junin to Cosquin | 496 km |
Distance from Junin to Aguilares | 909 km |
Distance from Junin to Anatuya | 702 km |
Distance from Junin to Diamante | 281 km |
Distance from Junin to Caucete | 758 km |