Distance from to

Distance from San Fernando del Valle de Catamarca to Junin

Distance from San Fernando del Valle de Catamarca to Junín is 819 kilometers. This air travel distance is equal to 509 miles.

The air travel (bird fly) shortest distance between San Fernando del Valle de Catamarca and Junín is 819 km= 509 miles.

If you travel with an airplane (which has average speed of 560 miles) from San Fernando del Valle de Catamarca to Junin, It takes 0.91 hours to arrive.

San Fernando del Valle de Catamarca

San Fernando del Valle de Catamarca is located in Argentina.

GPS Coordinates (DMS)28° 28´ 10.4520'' S
65° 47´ 6.8640'' W
Latitude-28.46957
Longitude-65.78524
Altitude545 m
CountryArgentina

San Fernando del Valle de Catamarca Distances to Cities

San Fernando del Valle de CatamarcaDistance
Distance from San Fernando Del Valle De Catamarca to Parana623 km
Distance from San Fernando Del Valle De Catamarca to Rosario699 km
Distance from San Fernando Del Valle De Catamarca to Rio Gallegos2,587 km
Distance from San Fernando Del Valle De Catamarca to Rawson1,647 km
Distance from San Fernando Del Valle De Catamarca to Machagai591 km

Junin

Junin is located in Argentina.

GPS Coordinates34° 35´ 1.7520'' S
60° 56´ 35.9520'' W
Latitude-34.58382
Longitude-60.94332
Altitude83 m
CountryArgentina

Junín Distances to Cities

JunínDistance
Distance from Junin to Cosquin496 km
Distance from Junin to Aguilares909 km
Distance from Junin to Anatuya702 km
Distance from Junin to Diamante281 km
Distance from Junin to Caucete758 km

Map of San Fernando del Valle de Catamarca

Map of Junin