Distance from Salisbury to Jefferson City
Distance from Salisbury to Jefferson City is 1,445 kilometers. This air travel distance is equal to 898 miles.
The air travel (bird fly) shortest distance between Salisbury and Jefferson City is 1,445 km or 898 miles.
If you travel with an airplane (which has average speed of 560 miles) from Salisbury to Jefferson City, It takes 1.6 hours to arrive.
Salisbury
Salisbury is located in United States.
| GPS Coordinates (DMS) | 38° 21´ 38.4120'' N 75° 35´ 57.7320'' W |
|---|---|
| Latitude | 38.36067 |
| Longitude | -75.59937 |
| Altitude | 10 m |
| Country | United States |
Salisbury Distances to Cities
| Salisbury | Distance |
|---|---|
| Distance from Salisbury Md to Elizabeth | 282 km |
| Distance from Salisbury Md to Shawnee Ok | 1,927 km |
| Distance from Salisbury Md to Hackensack | 311 km |
| Distance from Salisbury Md to Denver | 2,537 km |
| Distance from Salisbury Md to Suffolk | 201 km |
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |