Distance from Salekhard to Jamestown
Distance from Salekhard to Jamestown is 10,858 kilometers. This air travel distance is equal to 6,747 miles.
The air travel (bird fly) shortest distance between Salekhard and Jamestown is 10,858 km or 6,747 miles.
If you travel with an airplane (which has average speed of 560 miles) from Salekhard to Jamestown, It takes 12.05 hours to arrive.
Salekhard
Salekhard is located in Russia.
| GPS Coordinates (DMS) | 66° 31´ 48.0000'' N 66° 36´ 6.9840'' E |
|---|---|
| Latitude | 66.53000 |
| Longitude | 66.60194 |
| Altitude | 26 m |
| Country | Russia |
Salekhard Distances to Cities
| Salekhard | Distance |
|---|---|
| Distance from Salekhard to Jamestown | 10,858 km |
Jamestown
Jamestown is located in Saint Helena.
| GPS Coordinates | 15° 56´ 19.3920'' S 5° 43´ 0.3000'' W |
|---|---|
| Latitude | -15.93872 |
| Longitude | -5.71675 |
| Altitude | 426 m |
| Country | Saint Helena |