Distance from Saint Andrew to Chukotskiy Avtonomnyy Okrug
Distance from Saint Andrew to Chukotskiy Avtonomnyy Okrug is 7,234 kilometers. This air travel distance is equal to 4,495 miles.
The air travel (bird fly) shortest distance between Saint Andrew and Chukotskiy Avtonomnyy Okrug is 7,234 km= 4,495 miles.
If you travel with an airplane (which has average speed of 560 miles) from Saint Andrew to Chukotskiy Avtonomnyy Okrug, It takes 8.03 hours to arrive.
Saint Andrew
Saint Andrew is located in Guernsey.
| GPS Coordinates (DMS) | 49° 26´ 45.5280'' N 2° 34´ 29.5680'' W |
|---|---|
| Latitude | 49.44598 |
| Longitude | -2.57488 |
| Altitude | 70 m |
| Country | Guernsey |
Saint Andrew Distances to Cities
| Saint Andrew | Distance |
|---|---|
| Distance from Saint Andrew to Chukotskiy Avtonomnyy Okrug | 7,234 km |
Chukotskiy Avtonomnyy Okrug
Chukotskiy Avtonomnyy Okrug is located in Russia.
| GPS Coordinates | 65° 37´ 47.4240'' N 171° 41´ 42.7920'' E |
|---|---|
| Latitude | 65.62984 |
| Longitude | 171.69522 |
| Altitude | 60 m |
| Country | Russia |