Distance from Saginaw to Providence
Distance from Saginaw to Providence is 2,493 kilometers. This air travel distance is equal to 1,549 miles.
The air travel (bird fly) shortest distance between Saginaw and Providence is 2,493 km or 1,549 miles.
If you travel with an airplane (which has average speed of 560 miles) from Saginaw to Providence, It takes 2.77 hours to arrive.
Saginaw
Saginaw is located in United States.
| GPS Coordinates (DMS) | 32° 51´ 36.4680'' N 97° 21´ 50.0760'' W |
|---|---|
| Latitude | 32.86013 |
| Longitude | -97.36391 |
| Altitude | 227 m |
| Country | United States |
Saginaw Distances to Cities
| Saginaw | Distance |
|---|---|
| Distance from Saginaw Tx to Warren Mi | 1,651 km |
| Distance from Saginaw Tx to Four Corners Fl | 1,587 km |
| Distance from Saginaw Tx to The Colony | 51 km |
| Distance from Saginaw Tx to Honolulu | 6,055 km |
| Distance from Saginaw Tx to Watauga | 10 km |
Providence
Providence is located in United States.
| GPS Coordinates | 41° 49´ 26.3640'' N 71° 24´ 46.1880'' W |
|---|---|
| Latitude | 41.82399 |
| Longitude | -71.41283 |
| Altitude | -17 m |
| Country | United States |
Providence Distances to Cities
| Providence | Distance |
|---|---|
| Distance from Providence to Boston | 66 km |
| Distance from Providence to Smithfield | 16 km |
| Distance from Providence to Phoenix | 3,671 km |
| Distance from Providence to Virginia | 790 km |
| Distance from Providence to Palmdale | 4,117 km |