Distance from Sacramento to San Angelo
Distance from Sacramento to San Angelo is 2,072 kilometers. This air travel distance is equal to 1,287 miles.
The air travel (bird fly) shortest distance between Sacramento and San Angelo is 2,072 km or 1,287 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sacramento to San Angelo, It takes 2.3 hours to arrive.
Sacramento
Sacramento is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 53.6520'' N 121° 29´ 39.8400'' W |
|---|---|
| Latitude | 38.58157 |
| Longitude | -121.49440 |
| Altitude | 14 m |
| Country | United States |
Sacramento Distances to Cities
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |