Distance from Sacramento to Dickinson
Distance from Sacramento to Dickinson is 1,781 kilometers. This air travel distance is equal to 1,107 miles.
The air travel (bird fly) shortest distance between Sacramento and Dickinson is 1,781 km= 1,107 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sacramento to Dickinson, It takes 1.98 hours to arrive.
Sacramento
Sacramento is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 53.6520'' N 121° 29´ 39.8400'' W |
|---|---|
| Latitude | 38.58157 |
| Longitude | -121.49440 |
| Altitude | 14 m |
| Country | United States |
Sacramento Distances to Cities
Dickinson
Dickinson is located in United States.
| GPS Coordinates | 46° 52´ 45.0480'' N 102° 47´ 22.6320'' W |
|---|---|
| Latitude | 46.87918 |
| Longitude | -102.78962 |
| Altitude | 733 m |
| Country | United States |
Dickinson Distances to Cities
| Dickinson | Distance |
|---|---|
| Distance from Dickinson Nd to Spokane | 1,110 km |
| Distance from Dickinson Nd to Seattle | 1,478 km |
| Distance from Dickinson Nd to Mandan | 145 km |
| Distance from Dickinson Nd to Minot | 188 km |
| Distance from Dickinson Nd to Anchorage | 3,374 km |