Distance from Rhode Island to Seymour
Distance from Rhode Island to Seymour is 1,258 kilometers. This air travel distance is equal to 782 miles.
The air travel (bird fly) shortest distance between Rhode Island and Seymour is 1,258 km or 782 miles.
If you travel with an airplane (which has average speed of 560 miles) from Rhode Island to Seymour, It takes 1.4 hours to arrive.
Rhode Island
Rhode Island is located in United States.
| GPS Coordinates (DMS) | 41° 34´ 48.3240'' N 71° 28´ 38.7480'' W |
|---|---|
| Latitude | 41.58009 |
| Longitude | -71.47743 |
| Altitude | 26 m |
| Country | United States |
Rhode Island Distances to Cities
| Rhode Island | Distance |
|---|---|
| Distance from Rhode Island to Boston | 93 km |
| Distance from Rhode Island to Massachusetts | 92 km |
| Distance from Rhode Island to California | 4,123 km |
| Distance from Rhode Island to Pennsylvania | 480 km |
| Distance from Rhode Island to Virginia | 770 km |
Seymour
Seymour is located in United States.
| GPS Coordinates | 38° 57´ 33.1920'' N 85° 53´ 24.9000'' W |
|---|---|
| Latitude | 38.95922 |
| Longitude | -85.89025 |
| Altitude | 185 m |
| Country | United States |
Seymour Distances to Cities
| Seymour | Distance |
|---|---|
| Distance from Seymour In to New York City | 1,035 km |
| Distance from Seymour In to Mansfield Ma | 1,288 km |
| Distance from Seymour In to Fairland | 773 km |
| Distance from Seymour In to Waverly | 433 km |
| Distance from Seymour In to Farmington Mn | 872 km |