Distance from Randallstown to Jefferson City
Distance from Randallstown to Jefferson City is 1,334 kilometers. This air travel distance is equal to 829 miles.
The air travel (bird fly) shortest distance between Randallstown and Jefferson City is 1,334 km or 829 miles.
If you travel with an airplane (which has average speed of 560 miles) from Randallstown to Jefferson City, It takes 1.48 hours to arrive.
Randallstown
Randallstown is located in United States.
| GPS Coordinates (DMS) | 39° 22´ 2.3880'' N 76° 47´ 42.9000'' W |
|---|---|
| Latitude | 39.36733 |
| Longitude | -76.79525 |
| Altitude | 175 m |
| Country | United States |
Randallstown Distances to Cities
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |