Distance from Porticos de San Antonio to Tecamac de Felipe Villanueva
Distance from Pórticos de San Antonio to Tecámac de Felipe Villanueva is 2,286 kilometers. This air travel distance is equal to 1,420 miles.
The air travel (bird fly) shortest distance between Pórticos de San Antonio and Tecámac de Felipe Villanueva is 2,286 km= 1,420 miles.
If you travel with an airplane (which has average speed of 560 miles) from Porticos de San Antonio to Tecamac de Felipe Villanueva, It takes 2.54 hours to arrive.
Porticos de San Antonio
Porticos de San Antonio is located in Mexico.
| GPS Coordinates (DMS) | 32° 26´ 33.0000'' N 117° 2´ 3.0120'' W |
|---|---|
| Latitude | 32.44250 |
| Longitude | -117.03417 |
| Altitude | 275 m |
| Country | Mexico |
Pórticos de San Antonio Distances to Cities
Tecamac de Felipe Villanueva
Tecamac de Felipe Villanueva is located in Mexico.
| GPS Coordinates | 19° 42´ 47.0160'' N 98° 58´ 5.9880'' W |
|---|---|
| Latitude | 19.71306 |
| Longitude | -98.96833 |
| Altitude | 2274 m |
| Country | Mexico |
Tecámac de Felipe Villanueva Distances to Cities
| Tecámac de Felipe Villanueva | Distance |
|---|---|
| Distance from Tecamac De Felipe Villanueva 15 to Venceremos | 176 km |
| Distance from Tecamac De Felipe Villanueva 15 to Crucecita | 530 km |
| Distance from Tecamac De Felipe Villanueva 15 to Alborada Jaltenco | 12 km |