Distance from Palmyra Atoll to Balkanabat
Distance from Palmyra Atoll to Balkanabat is 13,747 kilometers. This air travel distance is equal to 8,542 miles.
The air travel (bird fly) shortest distance between Palmyra Atoll and Balkanabat is 13,747 km= 8,542 miles.
If you travel with an airplane (which has average speed of 560 miles) from Palmyra Atoll to Balkanabat, It takes 15.25 hours to arrive.
Palmyra Atoll
Palmyra Atoll is located in United States Minor Outlying Islands.
| GPS Coordinates (DMS) | 5° 52´ 59.9880'' N 162° 4´ 59.9880'' W |
|---|---|
| Latitude | 5.88333 |
| Longitude | -162.08333 |
| Altitude | 0 m |
| Country | United States Minor Outlying Islands |
Palmyra Atoll Distances to Cities
| Palmyra Atoll | Distance |
|---|---|
| Distance from Palmyra Atoll to Balkanabat | 13,747 km |
Balkanabat
Balkanabat is located in Turkmenistan.
| GPS Coordinates | 39° 30´ 38.7000'' N 54° 22´ 1.6680'' E |
|---|---|
| Latitude | 39.51075 |
| Longitude | 54.36713 |
| Altitude | 11 m |
| Country | Turkmenistan |