Distance from Ozumba de Alzate to Petrovsk
Distance from Ozumba de Alzate to Petrovsk is 11,377 kilometers. This air travel distance is equal to 7,069 miles.
The air travel (bird fly) shortest distance between Ozumba de Alzate and Petrovsk is 11,377 km or 7,069 miles.
If you travel with an airplane (which has average speed of 560 miles) from Ozumba de Alzate to Petrovsk, It takes 12.62 hours to arrive.
Ozumba de Alzate
Ozumba de Alzate is located in Mexico.
| GPS Coordinates (DMS) | 19° 2´ 12.8040'' N 98° 47´ 42.5760'' W |
|---|---|
| Latitude | 19.03689 |
| Longitude | -98.79516 |
| Altitude | 2342 m |
| Country | Mexico |
Ozumba de Alzate Distances to Cities
| Ozumba de Alzate | Distance |
|---|---|
| Distance from Ozumba De Alzate to Kasimov | 10,985 km |
| Distance from Ozumba De Alzate to Gorno Altaysk | 12,126 km |
| Distance from Ozumba De Alzate to Astrakhan | 12,036 km |
| Distance from Ozumba De Alzate to Petrovsk | 11,377 km |
| Distance from Ozumba De Alzate to Arsk | 11,177 km |