Distance from Oklahoma to San Angelo
Distance from Oklahoma to San Angelo is 502 kilometers. This air travel distance is equal to 312 miles.
The air travel (bird fly) shortest distance between Oklahoma and San Angelo is 502 km= 312 miles.
If you travel with an airplane (which has average speed of 560 miles) from Oklahoma to San Angelo, It takes 0.56 hours to arrive.
Oklahoma
Oklahoma is located in United States.
| GPS Coordinates (DMS) | 35° 0´ 27.9000'' N 97° 5´ 34.3680'' W |
|---|---|
| Latitude | 35.00775 |
| Longitude | -97.09288 |
| Altitude | 332 m |
| Country | United States |
Oklahoma Distances to Cities
| Oklahoma | Distance |
|---|---|
| Distance from Oklahoma to California | 2,021 km |
| Distance from Oklahoma to New York | 2,121 km |
| Distance from Oklahoma to Texas | 426 km |
| Distance from Oklahoma to Ohio | 1,385 km |
| Distance from Oklahoma to Colorado | 920 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |