Distance from Oklahoma City to Sayreville Junction
Distance from Oklahoma City to Sayreville Junction is 2,105 kilometers. This air travel distance is equal to 1,308 miles.
The air travel (bird fly) shortest distance between Oklahoma City and Sayreville Junction is 2,105 km or 1,308 miles.
If you travel with an airplane (which has average speed of 560 miles) from Oklahoma City to Sayreville Junction, It takes 2.34 hours to arrive.
Oklahoma City
Oklahoma City is located in United States.
| GPS Coordinates (DMS) | 35° 28´ 3.2160'' N 97° 30´ 59.1480'' W |
|---|---|
| Latitude | 35.46756 |
| Longitude | -97.51643 |
| Altitude | 395 m |
| Country | United States |
Oklahoma City Distances to Cities
| Oklahoma City | Distance |
|---|---|
| Distance from Oklahoma City to Dallas | 305 km |
| Distance from Oklahoma City to Ponca City | 143 km |
| Distance from Oklahoma City to Owasso | 174 km |
| Distance from Oklahoma City to Memphis | 680 km |
| Distance from Oklahoma City to Houston | 664 km |
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |