Distance from to

Distance from Nebraska to San Angelo

Distance from Nebraska to San Angelo is 1,114 kilometers. This air travel distance is equal to 692 miles.

The air travel (bird fly) shortest distance between Nebraska and San Angelo is 1,114 km= 692 miles.

If you travel with an airplane (which has average speed of 560 miles) from Nebraska to San Angelo, It takes 1.24 hours to arrive.

Nebraska

Nebraska is located in United States.

GPS Coordinates (DMS)41° 29´ 33.1440'' N
99° 54´ 6.5160'' W
Latitude41.49254
Longitude-99.90181
Altitude882 m
CountryUnited States

Nebraska Distances to Cities

NebraskaDistance
Distance from Nebraska to California1,762 km
Distance from Nebraska to New York2,169 km
Distance from Nebraska to Colorado543 km
Distance from Nebraska to Ohio1,433 km
Distance from Nebraska to South Dakota275 km

San Angelo

San Angelo is located in United States.

GPS Coordinates31° 27´ 49.5720'' N
100° 26´ 13.3440'' W
Latitude31.46377
Longitude-100.43704
Altitude564 m
CountryUnited States

San Angelo Distances to Cities

San AngeloDistance
Distance from San Angelo to Eagle1,948 km
Distance from San Angelo to West Odessa200 km
Distance from San Angelo to Moscow2,210 km
Distance from San Angelo to Twin Falls1,749 km
Distance from San Angelo to Albany Or2,455 km

Map of Nebraska

Map of San Angelo