Distance from Nebraska to San Angelo
Distance from Nebraska to San Angelo is 1,114 kilometers. This air travel distance is equal to 692 miles.
The air travel (bird fly) shortest distance between Nebraska and San Angelo is 1,114 km or 692 miles.
If you travel with an airplane (which has average speed of 560 miles) from Nebraska to San Angelo, It takes 1.24 hours to arrive.
Nebraska
Nebraska is located in United States.
| GPS Coordinates (DMS) | 41° 29´ 33.1440'' N 99° 54´ 6.5160'' W |
|---|---|
| Latitude | 41.49254 |
| Longitude | -99.90181 |
| Altitude | 882 m |
| Country | United States |
Nebraska Distances to Cities
| Nebraska | Distance |
|---|---|
| Distance from Nebraska to California | 1,762 km |
| Distance from Nebraska to New York | 2,169 km |
| Distance from Nebraska to Colorado | 543 km |
| Distance from Nebraska to Ohio | 1,433 km |
| Distance from Nebraska to South Dakota | 275 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |