Distance from Montgomery to Faribault
Distance from Montgomery to Faribault is 1,456 kilometers. This air travel distance is equal to 905 miles.
The air travel (bird fly) shortest distance between Montgomery and Faribault is 1,456 km= 905 miles.
If you travel with an airplane (which has average speed of 560 miles) from Montgomery to Faribault, It takes 1.62 hours to arrive.
Montgomery
Montgomery is located in United States.
| GPS Coordinates (DMS) | 32° 22´ 0.5160'' N 86° 17´ 59.8920'' W |
|---|---|
| Latitude | 32.36681 |
| Longitude | -86.29997 |
| Altitude | 76 m |
| Country | United States |
Montgomery Distances to Cities
Faribault
Faribault is located in United States.
| GPS Coordinates | 44° 17´ 41.8560'' N 93° 16´ 7.7880'' W |
|---|---|
| Latitude | 44.29496 |
| Longitude | -93.26883 |
| Altitude | 304 m |
| Country | United States |