Distance from Louisiana to San Angelo
Distance from Louisiana to San Angelo is 809 kilometers. This air travel distance is equal to 503 miles.
The air travel (bird fly) shortest distance between Louisiana and San Angelo is 809 km or 503 miles.
If you travel with an airplane (which has average speed of 560 miles) from Louisiana to San Angelo, It takes 0.9 hours to arrive.
Louisiana
Louisiana is located in United States.
| GPS Coordinates (DMS) | 30° 59´ 3.4800'' N 91° 57´ 44.3880'' W |
|---|---|
| Latitude | 30.98430 |
| Longitude | -91.96233 |
| Altitude | 13 m |
| Country | United States |
Louisiana Distances to Cities
| Louisiana | Distance |
|---|---|
| Distance from Louisiana to Texas | 762 km |
| Distance from Louisiana to Colorado | 1,573 km |
| Distance from Louisiana to California | 2,610 km |
| Distance from Louisiana to New York | 1,942 km |
| Distance from Louisiana to Virginia | 1,417 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |