Distance from Loski Potok to Sencur
Distance from Loški Potok to Šenčur is 63 kilometers. This air travel distance is equal to 39 miles.
The air travel (bird fly) shortest distance between Loški Potok and Šenčur is 63 km or 39 miles.
If you travel with an airplane (which has average speed of 560 miles) from Loski Potok to Sencur, It takes 0.07 hours to arrive.
Loski Potok
Loski Potok is located in Slovenia.
| GPS Coordinates (DMS) | 45° 41´ 27.4560'' N 14° 35´ 54.9600'' E |
|---|---|
| Latitude | 45.69096 |
| Longitude | 14.59860 |
| Altitude | 723 m |
| Country | Slovenia |
Loški Potok Distances to Cities
Sencur
Sencur is located in Slovenia.
| GPS Coordinates | 46° 14´ 36.1320'' N 14° 25´ 9.1920'' E |
|---|---|
| Latitude | 46.24337 |
| Longitude | 14.41922 |
| Altitude | 402 m |
| Country | Slovenia |