Distance from Kansas to San Angelo
Distance from Kansas to San Angelo is 856 kilometers. This air travel distance is equal to 532 miles.
The air travel (bird fly) shortest distance between Kansas and San Angelo is 856 km or 532 miles.
If you travel with an airplane (which has average speed of 560 miles) from Kansas to San Angelo, It takes 0.95 hours to arrive.
Kansas
Kansas is located in United States.
| GPS Coordinates (DMS) | 39° 0´ 42.8400'' N 98° 29´ 3.3000'' W |
|---|---|
| Latitude | 39.01190 |
| Longitude | -98.48425 |
| Altitude | 465 m |
| Country | United States |
Kansas Distances to Cities
| Kansas | Distance |
|---|---|
| Distance from Kansas to Texas | 792 km |
| Distance from Kansas to California | 1,854 km |
| Distance from Kansas to New York | 2,096 km |
| Distance from Kansas to Colorado | 632 km |
| Distance from Kansas to North Carolina | 1,758 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |