Distance from Jefferson City to Wilkinsburg
Distance from Jefferson City to Wilkinsburg is 1,076 kilometers. This air travel distance is equal to 669 miles.
The air travel (bird fly) shortest distance between Jefferson City and Wilkinsburg is 1,076 km or 669 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Wilkinsburg, It takes 1.19 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Wilkinsburg
Wilkinsburg is located in United States.
| GPS Coordinates | 40° 26´ 30.2640'' N 79° 52´ 55.1640'' W |
|---|---|
| Latitude | 40.44174 |
| Longitude | -79.88199 |
| Altitude | 288 m |
| Country | United States |
Wilkinsburg Distances to Cities
| Wilkinsburg | Distance |
|---|---|
| Distance from Wilkinsburg to Santa Monica | 3,471 km |
| Distance from Wilkinsburg to San Diego | 3,417 km |
| Distance from Wilkinsburg to West Jordan | 2,701 km |
| Distance from Wilkinsburg to South Jordan | 2,701 km |
| Distance from Wilkinsburg to De Pere | 806 km |