Distance from Jefferson City to Watauga
Distance from Jefferson City to Watauga is 783 kilometers. This air travel distance is equal to 487 miles.
The air travel (bird fly) shortest distance between Jefferson City and Watauga is 783 km= 487 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Watauga, It takes 0.87 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Watauga
Watauga is located in United States.
| GPS Coordinates | 32° 51´ 28.4760'' N 97° 15´ 17.0640'' W |
|---|---|
| Latitude | 32.85791 |
| Longitude | -97.25474 |
| Altitude | 188 m |
| Country | United States |
Watauga Distances to Cities
| Watauga | Distance |
|---|---|
| Distance from Watauga to Plum | 1,775 km |
| Distance from Watauga to Weatherford | 52 km |
| Distance from Watauga to Parker | 1,000 km |
| Distance from Watauga to Hobbs | 551 km |
| Distance from Watauga to Amarillo | 497 km |