Distance from Jefferson City to Warwick
Distance from Jefferson City to Warwick is 1,798 kilometers. This air travel distance is equal to 1,117 miles.
The air travel (bird fly) shortest distance between Jefferson City and Warwick is 1,798 km or 1,117 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Warwick, It takes 2 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Warwick
Warwick is located in United States.
| GPS Coordinates | 41° 42´ 0.3600'' N 71° 24´ 58.2120'' W |
|---|---|
| Latitude | 41.70010 |
| Longitude | -71.41617 |
| Altitude | -9 m |
| Country | United States |
Warwick Distances to Cities
| Warwick | Distance |
|---|---|
| Distance from Warwick to Patterson | 4,237 km |
| Distance from Warwick to Cheshire | 126 km |
| Distance from Warwick to La Mesa | 4,116 km |
| Distance from Warwick to San Pedro | 4,173 km |
| Distance from Warwick to Laguna Beach | 4,141 km |