Distance from Jefferson City to Warrensburg
Distance from Jefferson City to Warrensburg is 138 kilometers. This air travel distance is equal to 86 miles.
The air travel (bird fly) shortest distance between Jefferson City and Warrensburg is 138 km or 86 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Warrensburg, It takes 0.15 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Warrensburg
Warrensburg is located in United States.
| GPS Coordinates | 38° 45´ 46.0440'' N 93° 44´ 9.7800'' W |
|---|---|
| Latitude | 38.76279 |
| Longitude | -93.73605 |
| Altitude | 270 m |
| Country | United States |
Warrensburg Distances to Cities
| Warrensburg | Distance |
|---|---|
| Distance from Warrensburg to Dallas | 719 km |
| Distance from Warrensburg to Virginia Beach | 1,576 km |
| Distance from Warrensburg to Iowa City | 373 km |
| Distance from Warrensburg to Los Angeles | 2,252 km |
| Distance from Warrensburg to West Lafayette | 615 km |