Distance from to

Distance from Jefferson City to Walnut

Distance from Jefferson City to Walnut is 2,354 kilometers. This air travel distance is equal to 1,463 miles.

The air travel (bird fly) shortest distance between Jefferson City and Walnut is 2,354 km= 1,463 miles.

If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Walnut, It takes 2.61 hours to arrive.

Jefferson City

Jefferson City is located in United States.

GPS Coordinates (DMS)38° 34´ 36.1200'' N
92° 10´ 24.6720'' W
Latitude38.57670
Longitude-92.17352
Altitude195 m
CountryUnited States

Jefferson City Distances to Cities

Jefferson CityDistance
Distance from Jefferson City to Sacramento2,544 km
Distance from Jefferson City to Boston1,834 km
Distance from Jefferson City to San Francisco2,640 km
Distance from Jefferson City to Los Angeles2,386 km
Distance from Jefferson City to Dallas767 km

Walnut

Walnut is located in United States.

GPS Coordinates34° 1´ 13.0440'' N
117° 51´ 55.2240'' W
Latitude34.02029
Longitude-117.86534
Altitude173 m
CountryUnited States

Walnut Distances to Cities

WalnutDistance
Distance from Walnut to Altamont970 km
Distance from Walnut to Whittier16 km
Distance from Walnut to Dodge City1,661 km
Distance from Walnut to West Hollywood46 km
Distance from Walnut to Bonney Lake1,505 km

Map of Jefferson City

Map of Walnut