Distance from Jefferson City to Walnut
Distance from Jefferson City to Walnut is 2,354 kilometers. This air travel distance is equal to 1,463 miles.
The air travel (bird fly) shortest distance between Jefferson City and Walnut is 2,354 km or 1,463 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Walnut, It takes 2.61 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Walnut
Walnut is located in United States.
| GPS Coordinates | 34° 1´ 13.0440'' N 117° 51´ 55.2240'' W |
|---|---|
| Latitude | 34.02029 |
| Longitude | -117.86534 |
| Altitude | 173 m |
| Country | United States |
Walnut Distances to Cities
| Walnut | Distance |
|---|---|
| Distance from Walnut to Altamont | 970 km |
| Distance from Walnut to Whittier | 16 km |
| Distance from Walnut to Dodge City | 1,661 km |
| Distance from Walnut to West Hollywood | 46 km |
| Distance from Walnut to Bonney Lake | 1,505 km |