Distance from Jefferson City to Walnut Creek
Distance from Jefferson City to Walnut Creek is 2,606 kilometers. This air travel distance is equal to 1,619 miles.
The air travel (bird fly) shortest distance between Jefferson City and Walnut Creek is 2,606 km or 1,619 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Walnut Creek, It takes 2.89 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Walnut Creek
Walnut Creek is located in United States.
| GPS Coordinates | 37° 54´ 22.7160'' N 122° 3´ 53.8560'' W |
|---|---|
| Latitude | 37.90631 |
| Longitude | -122.06496 |
| Altitude | 54 m |
| Country | United States |
Walnut Creek Distances to Cities
| Walnut Creek | Distance |
|---|---|
| Distance from Walnut Creek to North Las Vegas | 646 km |
| Distance from Walnut Creek to West Sacramento | 88 km |
| Distance from Walnut Creek to Elko | 633 km |
| Distance from Walnut Creek to Eureka | 369 km |
| Distance from Walnut Creek to Arcata | 372 km |