Distance from Jefferson City to Wailuku
Distance from Jefferson City to Wailuku is 6,392 kilometers. This air travel distance is equal to 3,972 miles.
The air travel (bird fly) shortest distance between Jefferson City and Wailuku is 6,392 km or 3,972 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Wailuku, It takes 7.09 hours to arrive.
Jefferson City
Jefferson City is located in United States.
GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
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Latitude | 38.57670 |
Longitude | -92.17352 |
Altitude | 195 m |
Country | United States |
Jefferson City Distances to Cities
Jefferson City | Distance |
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Distance from Jefferson City to Sacramento | 2,544 km |
Distance from Jefferson City to Boston | 1,834 km |
Distance from Jefferson City to San Francisco | 2,640 km |
Distance from Jefferson City to Los Angeles | 2,386 km |
Distance from Jefferson City to Dallas | 767 km |
Wailuku
Wailuku is located in United States.
GPS Coordinates | 20° 53´ 27.9960'' N 156° 30´ 16.9920'' W |
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Latitude | 20.89111 |
Longitude | -156.50472 |
Altitude | 79 m |
Country | United States |
Wailuku Distances to Cities
Wailuku | Distance |
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Distance from Wailuku to Honolulu | 148 km |
Distance from Wailuku to Hilo | 196 km |
Distance from Wailuku to Anchorage | 4,508 km |
Distance from Wailuku to Fairbanks | 4,925 km |