Distance from Jefferson City to Virginia Beach
Distance from Jefferson City to Virginia Beach is 1,439 kilometers. This air travel distance is equal to 894 miles.
The air travel (bird fly) shortest distance between Jefferson City and Virginia Beach is 1,439 km or 894 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Virginia Beach, It takes 1.6 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Virginia Beach
Virginia Beach is located in United States.
| GPS Coordinates | 36° 51´ 10.5480'' N 75° 58´ 40.7640'' W |
|---|---|
| Latitude | 36.85293 |
| Longitude | -75.97799 |
| Altitude | 4 m |
| Country | United States |
Virginia Beach Distances to Cities
| Virginia Beach | Distance |
|---|---|
| Distance from Virginia Beach to Morristown Nj | 457 km |
| Distance from Virginia Beach to Los Angeles | 3,818 km |
| Distance from Virginia Beach to Sunnyvale | 4,052 km |
| Distance from Virginia Beach to Staten Island | 442 km |
| Distance from Virginia Beach to Port Angeles | 4,026 km |