Distance from Jefferson City to Van Nuys
Distance from Jefferson City to Van Nuys is 2,399 kilometers. This air travel distance is equal to 1,491 miles.
The air travel (bird fly) shortest distance between Jefferson City and Van Nuys is 2,399 km or 1,491 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Van Nuys, It takes 2.66 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Van Nuys
Van Nuys is located in United States.
| GPS Coordinates | 34° 11´ 12.0120'' N 118° 26´ 56.2920'' W |
|---|---|
| Latitude | 34.18667 |
| Longitude | -118.44897 |
| Altitude | 220 m |
| Country | United States |
Van Nuys Distances to Cities
| Van Nuys | Distance |
|---|---|
| Distance from Van Nuys to West Puente Valley | 47 km |
| Distance from Van Nuys to Whittier | 45 km |
| Distance from Van Nuys to Westminster Ca | 63 km |
| Distance from Van Nuys to Honolulu | 4,109 km |
| Distance from Van Nuys to Salem Or | 1,257 km |