Distance from Jefferson City to Swansea
Distance from Jefferson City to Swansea is 1,817 kilometers. This air travel distance is equal to 1,129 miles.
The air travel (bird fly) shortest distance between Jefferson City and Swansea is 1,817 km or 1,129 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Swansea, It takes 2.02 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Swansea
Swansea is located in United States.
| GPS Coordinates | 41° 44´ 53.3760'' N 71° 11´ 23.1720'' W |
|---|---|
| Latitude | 41.74816 |
| Longitude | -71.18977 |
| Altitude | -9 m |
| Country | United States |
Swansea Distances to Cities
| Swansea | Distance |
|---|---|
| Distance from Swansea to Kings Park | 198 km |
| Distance from Swansea to Kent Oh | 852 km |
| Distance from Swansea to North Kingstown | 32 km |
| Distance from Swansea to Cheshire | 145 km |
| Distance from Swansea to Kendall West | 1,972 km |