Distance from Jefferson City to Susanville
Distance from Jefferson City to Susanville is 2,448 kilometers. This air travel distance is equal to 1,521 miles.
The air travel (bird fly) shortest distance between Jefferson City and Susanville is 2,448 km or 1,521 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Susanville, It takes 2.72 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Susanville
Susanville is located in United States.
| GPS Coordinates | 40° 24´ 58.6080'' N 120° 39´ 10.8360'' W |
|---|---|
| Latitude | 40.41628 |
| Longitude | -120.65301 |
| Altitude | 1280 m |
| Country | United States |
Susanville Distances to Cities
| Susanville | Distance |
|---|---|
| Distance from Susanville to Klamath Falls | 222 km |
| Distance from Susanville to Roseburg | 383 km |
| Distance from Susanville to Elko | 416 km |
| Distance from Susanville to Coos Bay | 441 km |
| Distance from Susanville to Salt Lake City | 742 km |