Distance from Jefferson City to Shakopee
Distance from Jefferson City to Shakopee is 700 kilometers. This air travel distance is equal to 435 miles.
The air travel (bird fly) shortest distance between Jefferson City and Shakopee is 700 km or 435 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Shakopee, It takes 0.78 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Shakopee
Shakopee is located in United States.
| GPS Coordinates | 44° 47´ 52.8720'' N 93° 31´ 36.8400'' W |
|---|---|
| Latitude | 44.79802 |
| Longitude | -93.52690 |
| Altitude | 226 m |
| Country | United States |
Shakopee Distances to Cities
| Shakopee | Distance |
|---|---|
| Distance from Shakopee to Winona | 172 km |
| Distance from Shakopee to Menasha | 409 km |
| Distance from Shakopee to Fargo | 343 km |
| Distance from Shakopee to Appleton | 411 km |
| Distance from Shakopee to Sioux Falls | 289 km |