Distance from Jefferson City to Seymour
Distance from Jefferson City to Seymour is 1,657 kilometers. This air travel distance is equal to 1,030 miles.
The air travel (bird fly) shortest distance between Jefferson City and Seymour is 1,657 km= 1,030 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Seymour, It takes 1.84 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Seymour
Seymour is located in United States.
| GPS Coordinates | 41° 23´ 48.3360'' N 73° 4´ 33.3840'' W |
|---|---|
| Latitude | 41.39676 |
| Longitude | -73.07594 |
| Altitude | 30 m |
| Country | United States |
Seymour Distances to Cities
| Seymour | Distance |
|---|---|
| Distance from Seymour Ct to Torrance | 4,036 km |
| Distance from Seymour Ct to Orange Ca | 3,998 km |
| Distance from Seymour Ct to Cambridge | 196 km |
| Distance from Seymour Ct to Albany Ca | 4,186 km |
| Distance from Seymour Ct to Bedford Nh | 215 km |