Distance from Jefferson City to Seaford
Distance from Jefferson City to Seaford is 1,618 kilometers. This air travel distance is equal to 1,005 miles.
The air travel (bird fly) shortest distance between Jefferson City and Seaford is 1,618 km or 1,005 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Seaford, It takes 1.8 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Seaford
Seaford is located in United States.
| GPS Coordinates | 40° 39´ 57.3480'' N 73° 29´ 17.4480'' W |
|---|---|
| Latitude | 40.66593 |
| Longitude | -73.48818 |
| Altitude | 5 m |
| Country | United States |
Seaford Distances to Cities
| Seaford | Distance |
|---|---|
| Distance from Seaford to Middletown Ri | 209 km |
| Distance from Seaford to Los Angeles | 3,988 km |
| Distance from Seaford to Selden | 44 km |
| Distance from Seaford to Bridgewater | 98 km |
| Distance from Seaford to Huntington Beach | 3,986 km |