Distance from Jefferson City to Sayreville
Distance from Jefferson City to Sayreville is 1,543 kilometers. This air travel distance is equal to 959 miles.
The air travel (bird fly) shortest distance between Jefferson City and Sayreville is 1,543 km or 959 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Sayreville, It takes 1.71 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Sayreville
Sayreville is located in United States.
| GPS Coordinates | 40° 27´ 33.3720'' N 74° 21´ 39.5280'' W |
|---|---|
| Latitude | 40.45927 |
| Longitude | -74.36098 |
| Altitude | 24 m |
| Country | United States |
Sayreville Distances to Cities
| Sayreville | Distance |
|---|---|
| Distance from Sayreville to Monroe Wa | 3,833 km |
| Distance from Sayreville to Merrick | 72 km |
| Distance from Sayreville to Seaford | 77 km |
| Distance from Sayreville to South Orange | 33 km |
| Distance from Sayreville to Mckeesport | 467 km |