Distance from Jefferson City to Saratoga
Distance from Jefferson City to Saratoga is 2,617 kilometers. This air travel distance is equal to 1,626 miles.
The air travel (bird fly) shortest distance between Jefferson City and Saratoga is 2,617 km or 1,626 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Saratoga, It takes 2.9 hours to arrive.
Jefferson City
Jefferson City is located in United States.
GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
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Latitude | 38.57670 |
Longitude | -92.17352 |
Altitude | 195 m |
Country | United States |
Jefferson City Distances to Cities
Jefferson City | Distance |
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Distance from Jefferson City to Sacramento | 2,544 km |
Distance from Jefferson City to Boston | 1,834 km |
Distance from Jefferson City to San Francisco | 2,640 km |
Distance from Jefferson City to Los Angeles | 2,386 km |
Distance from Jefferson City to Dallas | 767 km |
Saratoga
Saratoga is located in United States.
GPS Coordinates | 37° 15´ 49.7880'' N 122° 1´ 22.8360'' W |
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Latitude | 37.26383 |
Longitude | -122.02301 |
Altitude | 128 m |
Country | United States |
Saratoga Distances to Cities
Saratoga | Distance |
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Distance from Saratoga to South Lake Tahoe | 257 km |
Distance from Saratoga to South San Francisco | 55 km |
Distance from Saratoga to Vacaville | 121 km |
Distance from Saratoga to Cheyenne | 1,544 km |
Distance from Saratoga to Lafayette Co | 1,503 km |