Distance from Jefferson City to San Tan Valley
Distance from Jefferson City to San Tan Valley is 1,843 kilometers. This air travel distance is equal to 1,145 miles.
The air travel (bird fly) shortest distance between Jefferson City and San Tan Valley is 1,843 km or 1,145 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to San Tan Valley, It takes 2.04 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
San Tan Valley
San Tan Valley is located in United States.
| GPS Coordinates | 33° 11´ 27.9600'' N 111° 31´ 40.8000'' W |
|---|---|
| Latitude | 33.19110 |
| Longitude | -111.52800 |
| Altitude | 461 m |
| Country | United States |
San Tan Valley Distances to Cities
| San Tan Valley | Distance |
|---|---|
| Distance from San Tan Valley to Cranberry Township | 2,902 km |
| Distance from San Tan Valley to Enchanted Hills | 513 km |
| Distance from San Tan Valley to Oak Hill | 3,121 km |
| Distance from San Tan Valley to Dixiana | 2,308 km |
| Distance from San Tan Valley to Warren Township | 3,373 km |