Distance from Jefferson City to San Jacinto
Distance from Jefferson City to San Jacinto is 2,285 kilometers. This air travel distance is equal to 1,420 miles.
The air travel (bird fly) shortest distance between Jefferson City and San Jacinto is 2,285 km or 1,420 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to San Jacinto, It takes 2.54 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
San Jacinto
San Jacinto is located in United States.
| GPS Coordinates | 33° 47´ 2.0760'' N 116° 57´ 31.1040'' W |
|---|---|
| Latitude | 33.78391 |
| Longitude | -116.95864 |
| Altitude | 480 m |
| Country | United States |