Distance from Jefferson City to Rosenberg
Distance from Jefferson City to Rosenberg is 1,055 kilometers. This air travel distance is equal to 656 miles.
The air travel (bird fly) shortest distance between Jefferson City and Rosenberg is 1,055 km= 656 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Rosenberg, It takes 1.17 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Rosenberg
Rosenberg is located in United States.
| GPS Coordinates | 29° 33´ 25.8480'' N 95° 48´ 30.8160'' W |
|---|---|
| Latitude | 29.55718 |
| Longitude | -95.80856 |
| Altitude | 35 m |
| Country | United States |
Rosenberg Distances to Cities
| Rosenberg | Distance |
|---|---|
| Distance from Rosenberg to Holland | 1,705 km |
| Distance from Rosenberg to Rotterdam | 2,440 km |
| Distance from Rosenberg to San Antonio | 261 km |
| Distance from Rosenberg to Stafford | 25 km |
| Distance from Rosenberg to Somerset Ma | 2,599 km |