Distance from Jefferson City to Orcutt
Distance from Jefferson City to Orcutt is 2,548 kilometers. This air travel distance is equal to 1,583 miles.
The air travel (bird fly) shortest distance between Jefferson City and Orcutt is 2,548 km or 1,583 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Orcutt, It takes 2.83 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Orcutt
Orcutt is located in United States.
| GPS Coordinates | 34° 51´ 54.9360'' N 120° 26´ 9.6000'' W |
|---|---|
| Latitude | 34.86526 |
| Longitude | -120.43600 |
| Altitude | 113 m |
| Country | United States |
Orcutt Distances to Cities
| Orcutt | Distance |
|---|---|
| Distance from Orcutt to San Pedro | 234 km |
| Distance from Orcutt to Oak Hill | 3,827 km |
| Distance from Orcutt to Pinole | 386 km |
| Distance from Orcutt to Pullman | 1,346 km |
| Distance from Orcutt to Sacramento | 423 km |