Distance from Jefferson City to Norton Shores
Distance from Jefferson City to Norton Shores is 713 kilometers. This air travel distance is equal to 443 miles.
The air travel (bird fly) shortest distance between Jefferson City and Norton Shores is 713 km or 443 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Norton Shores, It takes 0.79 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Norton Shores
Norton Shores is located in United States.
| GPS Coordinates | 43° 10´ 8.0400'' N 86° 15´ 50.2200'' W |
|---|---|
| Latitude | 43.16890 |
| Longitude | -86.26395 |
| Altitude | 191 m |
| Country | United States |
Norton Shores Distances to Cities
| Norton Shores | Distance |
|---|---|
| Distance from Norton Shores to Santa Fe | 1,880 km |
| Distance from Norton Shores to Avon Lake | 395 km |
| Distance from Norton Shores to Milwaukee | 134 km |
| Distance from Norton Shores to Ashtabula | 472 km |
| Distance from Norton Shores to South Euclid | 432 km |