Distance from Jefferson City to Mount Prospect
Distance from Jefferson City to Mount Prospect is 529 kilometers. This air travel distance is equal to 329 miles.
The air travel (bird fly) shortest distance between Jefferson City and Mount Prospect is 529 km= 329 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Mount Prospect, It takes 0.59 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Mount Prospect
Mount Prospect is located in United States.
| GPS Coordinates | 42° 3´ 59.1120'' N 87° 56´ 14.2440'' W |
|---|---|
| Latitude | 42.06642 |
| Longitude | -87.93729 |
| Altitude | 205 m |
| Country | United States |