Distance from Jefferson City to Martinsburg
Distance from Jefferson City to Martinsburg is 1,233 kilometers. This air travel distance is equal to 766 miles.
The air travel (bird fly) shortest distance between Jefferson City and Martinsburg is 1,233 km or 766 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Martinsburg, It takes 1.37 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Martinsburg
Martinsburg is located in United States.
| GPS Coordinates | 39° 27´ 22.3560'' N 77° 57´ 50.0040'' W |
|---|---|
| Latitude | 39.45621 |
| Longitude | -77.96389 |
| Altitude | 139 m |
| Country | United States |
Martinsburg Distances to Cities
| Martinsburg | Distance |
|---|---|
| Distance from Martinsburg to Los Angeles | 3,616 km |
| Distance from Martinsburg to Framingham | 635 km |
| Distance from Martinsburg to Steubenville | 250 km |
| Distance from Martinsburg to Pittsburgh | 205 km |
| Distance from Martinsburg to Dix Hills | 422 km |