Distance from Jefferson City to Lompoc
Distance from Jefferson City to Lompoc is 2,558 kilometers. This air travel distance is equal to 1,589 miles.
The air travel (bird fly) shortest distance between Jefferson City and Lompoc is 2,558 km= 1,589 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Lompoc, It takes 2.84 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Lompoc
Lompoc is located in United States.
| GPS Coordinates | 34° 38´ 20.9400'' N 120° 27´ 28.5840'' W |
|---|---|
| Latitude | 34.63915 |
| Longitude | -120.45794 |
| Altitude | 34 m |
| Country | United States |
Lompoc Distances to Cities
| Lompoc | Distance |
|---|---|
| Distance from Lompoc to Yucca Valley | 375 km |
| Distance from Lompoc to Paso Robles | 112 km |
| Distance from Lompoc to Los Angeles | 214 km |
| Distance from Lompoc to Monterey Park | 224 km |
| Distance from Lompoc to Salinas | 251 km |