Distance from Jefferson City to Lawndale
Distance from Jefferson City to Lawndale is 2,402 kilometers. This air travel distance is equal to 1,493 miles.
The air travel (bird fly) shortest distance between Jefferson City and Lawndale is 2,402 km or 1,493 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Lawndale, It takes 2.67 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Lawndale
Lawndale is located in United States.
| GPS Coordinates | 33° 53´ 14.0640'' N 118° 21´ 9.2520'' W |
|---|---|
| Latitude | 33.88724 |
| Longitude | -118.35257 |
| Altitude | 19 m |
| Country | United States |
Lawndale Distances to Cities
| Lawndale | Distance |
|---|---|
| Distance from Lawndale to Los Angeles | 21 km |
| Distance from Lawndale to Lynwood | 14 km |
| Distance from Lawndale to Paso Robles | 288 km |
| Distance from Lawndale to Temecula | 120 km |
| Distance from Lawndale to Lompoc | 211 km |